Question #118955
At rest, a uranium atom U238 decays into an alpha particle and a thorium atom Th234. Radioactive decay is like an elastic collision run backward; the particles begin stuck together and end by flying apart. In this process 8.64x10-13 J of energy is liberated. The mass of an alpha particle is 6.68x10-27 kg, and the mass of thorium is 3.91x10-25 kg. What is the momentum of the alpha particle after the decay?
1
Expert's answer
2020-06-01T13:12:39-0400
Mumv=0p=mv=MuMu-mv=0\\ p=mv=Mu

E=0.5Mu2+0.5mu2=p22M+p22mE=0.5Mu^2+0.5mu^2=\frac{p^2}{2M}+\frac{p^2}{2m}

(8.641013)=p22(3.911025)+p22(6.681027)(8.64\cdot10^{-13})=\frac{p^2}{2(3.91\cdot10^{-25})}+\frac{p^2}{2(6.68\cdot10^{-27})}

p=1.071019kgmsp=1.07\cdot10^{-19}\frac{kg\cdot m}{s}


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