From the formula for the activity of a substance
C=M⋅T1/20.693⋅NA⋅m
Where
NA=6.022⋅1026 - Avogadro number
M - atomic mass of the radioactive element
T1/2=4.77⋅60=286.2s - half-life of a radioactive element
m -mass of a radioactive element
Note
m=0.693⋅NAC⋅M⋅T1/2
Given that
1Ci=3.7⋅1010decays/s
m=0.693⋅6.022⋅10261500⋅206.977⋅(4.77⋅60)⋅3.7⋅1010⋅106=7.878⋅10−3μg
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