Question #118618
A radioactive sample of thallium-207 has a half-life of 4.77 minutes has an activity of 1500 Ci.
What is the mass of the sample of thallium? (to 2 s.f and in µg)
1
Expert's answer
2020-06-01T14:18:24-0400

Activity of the sample is R=1500Ci=1500(3.71010)R=1500 Ci=1500(3.7*10^{10})

=5.551013decays/s=5.55*10^{13} decays/s

The expression for the activity of the sample is

R=ln2NAmMT1/2=0.693NAmMT1/2R= \frac{ln2 N_A m}{M T_{1/2}}=\frac{0.693 N_A m}{M T_{1/2}}

Here NAN_A Avogadro number.

mm is the mass of sample.

MM is the molecular mass.

Isolate the above equation for mm ,

m=RMT1/20.693NAm=\frac{RM T_{1/2}}{0.693 N_A}

=(5.551013)(206.977103)(4.7760)0.693(6.0221023)=\frac{(5.55*10^{13})(206.977*10^{-3})(4.77*60)}{0.693 (6.022*10^{23})}

=7.99109kg=7.99106g=7.99μg=7.99*10^{-9} kg=7.99*10^{-6} g =7.99 \mu g


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