According to the Planck's formula, the energy correspondes to the wavelength λ=576,960nm (that is, the energy difference between two energy levels in the mercury atom) will be:
E=h⋅λc,
where h=4.14⋅10−15 eV⋅s is the Planck's constant and c=3⋅108m/s is the speed of light. Thus:
E=4.14⋅10−15 ⋅576.960⋅10−93⋅108≈2.15eV .
Answer. E = 2.15 eV.
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