Question #113589
A cannon fire a ball off of a 20.0 m high cliff. What is the range of the cannon if fired at 100.0 m/s at a 30.0 degree angle?
1
Expert's answer
2020-05-04T12:41:25-0400


here the total range will be R1+R2

we have to calculate R1+R2

first let's calculate R1

R1=v2sin2θ/2g=100×100×32×10×2=2503mv^2\sin2\theta/2g=\frac{100\times100\times\sqrt3}{2\times10\times2}=250\sqrt3m


and now let's calculate R2

the horizontal component of velocity=+30 cos30=153\sqrt3 m/s

vertical component of velocity =30 sin30=15 m/s

applying S=ut+0.5gt2

20=15t+5t2

on solving we get t=1 seconds (although it has two roots but the other one is negative and we know time cannot we negative )

R2=153\sqrt3 *1=153\sqrt3m


hence total range R1+R2 = 2653\sqrt3 m


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