Question #112603

3. If the half-life of an isotope is 3 years, what fraction of the isotope remains after 4 years? (put fraction in as decimal

Expert's answer

The radioactive decay law says

N(t)=N02t/t1/2N(t)=N_02^{-t/t_{1/2}}

Hence, the fraction of the isotope that remains after 4 years

N(4)/N0=24/3=0.40N(4)/N_0=2^{-4/3}=0.40

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