Question #109601

if 5000 J of work is used to raise a 102 kg crate to a shelf in a warehouse, how high was the crate raised? (express your answer in units of meters

Expert's answer

Work done is equal to change in potential energy

change in potential energy is equal to m(Δh)g=5000m(\Delta h)g=5000

102×Δh×10=5000Δh=4.9m102\times\Delta h\times10=5000\\\Delta h=4.9m

So the crate was raised by 4.9 metres


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