Question #89619
You are the captain of a spaceship that is circling through a binary star system. Due to the gravitational forces and the rocket engines, the orbit of your spaceship looks like that:

The position of your spaceship (in AU) at the time t (in days) is given by:
x= 5sin(t) y= sin(2t) z= 0
a) How long does it take your spaceship to circle the orbit once?
b) Find an equation that calculates the velocity v(t) of your spaceship at a given time t.
c) The two stars are positioned at the points (4,0,0) and (-4,0,0): what is the distance of your spaceship to the stars at the time t = π/2 ?
1
Expert's answer
2019-05-13T11:19:41-0400

a) Period of time to circe orbit at once equal to 2π6.282\pi \approx 6.28 days

b) Velocity (in AU per day):


vx(t)=dxdt=5cos(t)vy(t)=dydt=2cos(2t)v_x(t) = \frac{dx}{dt} = 5 \cos(t) \, \quad v_y(t) = \frac{dy}{dt} = 2 \cos(2t)

v(t)=vx2(t)+vy2(t)=25cos2(t)+4cos2(2t)v(t) = \sqrt{v_x^2 (t) + v_y^2 (t)} = \sqrt{25\cos^2(t) + 4\cos^2(2t)}

c) At time t=π/2,x=5,y=0,z=0t= \pi/2, \, x = 5,\, y= 0, \, z=0

Therefore, distance to the star at the point (4,0,0) is 1 a.u.,

to the star at the point (-4,0,0) is 9 a.u.


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