Question #89603
You are the captain of a spaceship that is circling through a binary star system. Due to the gravitational forces and the rocket engines, the orbit of your spaceship looks like that:
The position of your spaceship (in AU) at the time t (in days) is given by:
x = 5 sin(t) y = sin(2t) z = 0
(a) How long does it take your spaceship to circle the orbit once?
(b) Find an equation that calculates the velocity v(t) of your spaceship at a given time t.
(c) The two stars are positioned at the points (4, 0, 0) and (−4, 0, 0): What is the distance of your
spaceship to the stars at the time t =
π
2
?
Expert's answer
1
Expert's answer
2019-05-17T11:24:08-0400

a) The highest period is


T=2π6.28 daysT=2\pi \approx 6.28\ days

 b)


v=(dxdt,dydt,dzdt)\vec{v}=\left(\frac{dx}{dt},\frac{dy}{dt},\frac{dz}{dt}\right)


v=(5cost,2cos2t,0)\vec{v}=\left(5\cos{t},2\cos{2t},0\right)

The magnitude is


v=(5cost)2+(2cos2t)2v=\sqrt{(5\cos{t})^2+(2\cos{2t})^2}

c)


r=(5,0,0) AU\vec{r}=\left(5,0,0\right)\ AU

The distance from the first star is


xx0=54=1 AUx-x_0=5-4=1\ AU

The distance from the second star is


xx1=5(4)=9 AUx-x_1=5-(-4)=9\ AU


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS