Question

An energy of 5.35eV is stored by a molecule undergoing circulatory motion with an angular momentum of 0.5kgm^2s-1, determine its moment of inertia.

Answer 1

Answer on Question #81058, Physics / Astronomy | Astrophysics

Question:

An energy of $5.35\mathrm{eV}$ is stored by a molecule undergoing circulatory motion with an angular momentum of $0.5\mathrm{kgm}^{\wedge}2\mathrm{s}-1$ , determine its moment of inertia.

Solution:

The energy $W = \frac{J\omega^2}{2}$ , the angular momentum $L = J\omega$ , respectively $W = \frac{L^2}{2J}$ , therefore the moment of inertia $J = \frac{L^2}{2W} = \frac{0.25}{2\cdot 5.35\cdot 1.6\cdot 10^{-19}} = 1.5\cdot 10^{17}$ ( $\mathrm{kgm}^2$ ), what is evidently wrong because the angular momentum isn't correct.

The answer:

The moment of inertia $J = \frac{L^2}{2W} = \frac{0.25}{2\cdot 5.35\cdot 1.6\cdot 10^{-19}} = 1.5\cdot 10^{17}\mathrm{kgm}^2$ , what is evidently wrong, because the angular momentum (0.5kgm^2s-1) isn't correct.

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