Answer on Question 55065, Physics / Astronomy | Astrophysics
Ω¨=nΩn−1Ω˙
But from the question:
Ωn−1=ΩΩ˙, and so:Ω¨=nΩΩ˙Ω˙, and therefore:n=Ω˙2Ω¨Ω
For magnetic dipole radiation:
E˙=IΩΩ˙=3c22(BR2sina)2Ω4
Therefore, Ω˙∝Ω3, and therefore n=3.
Answer: n=3
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