Question #54985

Discuss Jeans criterion for the formation of stars and obtain an expression for Jeans mass
and Jeans length

Expert's answer

Answer on Question #54985, Physics / Astronomy | Astrophysics

Star formation begins in Giant Molecular Clouds (GMCs). The Milky Way has several thousand of these objects, each with masses of 104M<M<107M10^{4}\mathrm{M}_{\odot} < \mathrm{M} < 10^{7}\mathrm{M}_{\odot}, and sizes between 10 and 100 pc.

A cloud will collapse if the gravitational potential is stronger than its thermal (and magnetic) support. In other words Egrav>2Ei|\mathrm{E}_{\mathrm{grav}}| > 2\mathrm{E}_{\mathrm{i}}. As we just saw, the internal energy is:


Ei=0MT1γ1×PρdM=0MT1γ1×1μmHkTdME_{i} = \int_{0}^{M_{T}} \frac{1}{\gamma - 1} \times \frac{P}{\rho} dM = \int_{0}^{M_{T}} \frac{1}{\gamma - 1} \times \frac{1}{\mu m_{H}} k T dM


For simplicity, let's take a uniform density, isothermal cloud. For such a cloud:


Egrav=0RGM(r)rdM=35GM2R=2Ei=2γ1×1μmHkTM\left| E_{\text{grav}} \right| = \int_{0}^{R} \frac{GM(r)}{r} dM = \frac{3}{5} \frac{GM^{2}}{R} = 2E_{i} = \frac{2}{\gamma - 1} \times \frac{1}{\mu m_{H}} k TM


or:


MJ=53×2γ1×1GμmHkTRM_{J} = \frac{5}{3} \times \frac{2}{\gamma - 1} \times \frac{1}{G \mu m_{H}} k TR


All scales larger than this are unstable to collapse.

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