Question #45876

A white dwarf star has a mass of (10)30 kg and its luminousity is (10)24 (j)/s . Calculate how long it can survive with its present luminosity of its internal temperature is (10)7 k .
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Expert's answer

2014-09-09T11:16:38-0400

Answer on Question #45876 – Physics – Astronomy – Astrophysics

Question:

A white dwarf star has a mass of 103010^{30} kg and its luminosity is 102410^{24} J/s. Calculate how long it can survive with its present luminosity of its internal temperature is 10710^{7} K.

Answer:

The lifetime of stars is approximately proportional to M/L (mass/luminosity ratio).


Msun/Lsunlifetime of sunM_{\mathrm{sun}} / L_{\mathrm{sun}} \sim \text{lifetime of sun}Mwhite dwarf/Lwhite dwarflifetime of white dwarfM_{\mathrm{white~dwarf}} / L_{\mathrm{white~dwarf}} \sim \text{lifetime of white dwarf}Msun=1.988×1030 kgM_{\mathrm{sun}} = 1.988 \times 10^{30} \mathrm{~kg}Lsun=384.6×1024 J/s.L_{\mathrm{sun}} = 384.6 \times 10^{24} \mathrm{~J/s}.


The lifetime of sun is approximately 101010^{10} years.

We can make the following proportion:


1.988×1030 kg/384.6×1024 J/s=1010 years1.988 \times 10^{30} \mathrm{~kg} / 384.6 \times 10^{24} \mathrm{~J/s} = 10^{10} \mathrm{~years}1030 kg/1024 J/s=X years10^{30} \mathrm{~kg} / 10^{24} \mathrm{~J/s} = X \mathrm{~years}Then, X=101010301024÷1.9881030384.61024=10101030384.6102410241.9881030=193.51010 years\text{Then, } X = 10^{10} \cdot \frac{10^{30}}{10^{24}} \div \frac{1.988 \cdot 10^{30}}{384.6 \cdot 10^{24}} = 10^{10} \cdot \frac{10^{30} \cdot 384.6 \cdot 10^{24}}{10^{24} \cdot 1.988 \cdot 10^{30}} = 193.5 \cdot 10^{10} \mathrm{~years}


Answer: 193.51010193.5 \cdot 10^{10} years

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