Find the acceleration of a car a velocity of 60 m/s in a distance 360 m
Explanations & Calculations
(60 ms−1)2=02+2a(360 m)a=5 ms−2\qquad\qquad \begin{aligned} \small (60\,ms^{-1})^2&=\small 0^2+2a(360\,m)\\ \small a&=\small 5\,ms^{-2} \end{aligned}(60ms−1)2a=02+2a(360m)=5ms−2
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