Question

An aluminum cylinder has a volume of 60ml. Calculate the buoyant force that will be exerted on the cylinder when it is interested in

A. Water

B. Alcohol (density=0.78g/ml)

Answer 1

A: The force is

$$F_w=\rho_w gV=1000·9.8·(60·10^{-6})=0.59\text{ N}.$$

B: The force is

$$F_a=\rho_agV=780·9.8·(60·10^{-6})=0.46\text{ N}.$$