Answer to Question #254180 in Astronomy | Astrophysics for sabby

Question #254180

Mercury orbits the sun at a distance of 0.4 AU. What is mercury’s orbital period in earth

years? Keplers’s Third Law : T^2=d^3. T: orbital period in earth year. D: distance to sun

in astronomical units. 1 AU=150,000,000 or 1.5x10^8 km.


1
Expert's answer
2021-10-21T10:53:10-0400

Application of Kepler's third law gives us the following:

T2=d3T=d3=0.25 years.T^2=d^3→ T=\sqrt{ d^3}=0.25\text{ years}.


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