1. Planet x is 265 earth orbital radii from the sun, what is the period of revolution in earth year?
Solution
According to the third Kepler's law we have:
P planet 2 a planet 3 = P earth 2 a earth 3 \frac {P _ {\text {planet}} ^ {2}}{a _ {\text {planet}} ^ {3}} = \frac {P _ {\text {earth}} ^ {2}}{a _ {\text {earth}} ^ {3}} a planet 3 P planet 2 = a earth 3 P earth 2
Where
P planet , P earth , a planet , a earth P _ {\text {planet}}, P _ {\text {earth}}, a _ {\text {planet}}, a _ {\text {earth}} P planet , P earth , a planet , a earth
are the orbital period of planet, orbital period of Earth, radius of planet's orbit and radius of orbit of Earth.
We have
a planet = 265 a.u. a _ {\text {planet}} = 265 \text{a.u.} a planet = 265 a.u. P earth = 1 year P _ {\text {earth}} = 1 \text{year} P earth = 1 year a earth = 1 a.u. a _ {\text {earth}} = 1 \text{a.u.} a earth = 1 a.u.
where a.u. is the astronomical unit (distance between Sun-Earth)
Hence we have
P planet = P earth a planet 3 a earth 3 = 26 5 3 years ≈ 4313.89 years P _ {\text {planet}} = P _ {\text {earth}} \sqrt {\frac {a _ {\text {planet}} ^ {3}}{a _ {\text {earth}} ^ {3}}} = \sqrt {265^3} \text{years} \approx 4313.89 \text{years} P planet = P earth a earth 3 a planet 3 = 26 5 3 years ≈ 4313.89 years
**Answer:**
Revolution period is
P planet ≈ 4313.89 years P _ {\text {planet}} \approx 4313.89 \text{years} P planet ≈ 4313.89 years