Question #218971

You have used Cepheid variable to measure the distance to a nearby spiral galaxy. The spiral galaxy is 5.0 Mpc (megaparsecs) away. Three years ago, a Type 1a supernova was observed in this galaxy, and had a peak flux of 6.2 × 10-14W m-2.


You have just discovered a new Type 1a supernova in a very distant galaxy. This new supernova stayed bright for the same time as the one in the nearby spiral galaxy. The flux of the new supernova was 1.3 × 10-18W m-2.


What is the distance to the new supernova (in Mpc)?:


1
Expert's answer
2021-07-20T09:45:57-0400

If we don't take the cosmologic expansion into account, we assume the flux to be proportional to r2r^{-2} , so I1I2=r22r12,  r2=218r1=1.1  Gpc.\dfrac{I_1}{I_2} = \dfrac{r_2^2}{r_1^2}, \; r_2 = 218r_1 = 1.1\;\mathrm{Gpc}.


But if we take the expansion into account, we should write I=L4πr22(1+z)2I = \dfrac{L}{4\pi r_2^2(1+z)^2} . For such distances the redshift is approximately 0.2, if we calculate it in form of z=Hr2/cz = Hr_2/c , therefore, (1+z)21.5,(1+z)^2 \approx 1.5, (1+z)1.24(1+z)\approx 1.24 and we should correct the estimate of r2r_2 from the by 1/1.241/1.24 and get the value of 880 Mpc.


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