Question

Ø A proton travels with a speed of 5.02´10⁶ m/s in a direction that makes an angle of 60.0° with the direction of a magnetic field of magnitude 0.180 T in the positive x direction. What are the magnitudes of: a) Magnetic force on the proton. b) The proton's acceleration?

Answer 1

The magnitude:

$$F=qvB\sin\theta=1.25·10^{-13}\text{ N}.$$

The acceleration:

$$a=\frac Fm=7.50·10^{13}\text{ m/s}^2.$$