In 5 minutes, a current of 5 amps is established in a wire. How many coulombs and how many electrons pass through each cross section of this wire?
The current is
I=qt ⟹ q=It\displaystyle I = \frac{q}{t} \; \Longrightarrow \; q = ItI=tq⟹q=It
q=5A⋅5⋅60s=1500 Cq = 5 A \cdot5 \cdot 60 s = 1500\,Cq=5A⋅5⋅60s=1500C
One electron has charge 1.6⋅10−19 C1.6 \cdot 10^{-19} \, C1.6⋅10−19C. Then
N=q1.6⋅10−19=15001.6⋅10−19=937.5⋅1019=9.375⋅1021\displaystyle N = \frac{q}{1.6 \cdot 10^{-19}} = \frac{1500}{1.6 \cdot 10^{-19}} = 937.5 \cdot 10^{19} = 9.375 \cdot 10^{21}N=1.6⋅10−19q=1.6⋅10−191500=937.5⋅1019=9.375⋅1021
Answer: 1500 C, 9.375⋅10211500\; C, \, 9.375 \cdot 10^{21}1500C,9.375⋅1021
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