Question #176278

Our solar system is about 8.3 kpc from the centre of our galaxy. Using Newtons universal gravitation law and kepler's third law, calculate the approximate mass of our milky way if we know that the orbital velocity of the sun around the centre of the galaxy is 225 km/s


Expert's answer

We can find the approximate mass of our milky way as follows:


FNet=Fg,F_{Net}=F_g,MSunv2R=GMSunMMilky WayR2,\dfrac{M_{Sun}v^2}{R}=\dfrac{GM_{Sun}M_{Milky\ Way}}{R^2},v2=GMMilky WayR,v^2=\dfrac{GM_{Milky\ Way}}{R},MMilky Way=v2RG,M_{Milky\ Way}=\dfrac{v^2R}{G},MMilky Way=(225 kms1000 m1 km)28.3 kpc3.0861019 m1 kpc6.671011 Nm2kg2,M_{Milky\ Way}=\dfrac{(225\ \dfrac{km}{s}\cdot\dfrac{1000\ m}{1\ km})^2\cdot8.3\ kpc\cdot\dfrac{3.086\cdot10^{19}\ m}{1\ kpc}}{6.67\cdot10^{-11}\ \dfrac{Nm^2}{kg^2}},MMilky Way=1.941041 kg.M_{Milky\ Way}=1.94\cdot10^{41}\ kg.
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