Question #168826

A 1 kilogram object is located at a distance of 6.4x10 to the 6th m from the center of a larger object whose mass is 6 by 10 to the 24th kg. Find the gravitational attraction between them.


1
Expert's answer
2021-03-04T11:50:57-0500

According to the Newton's law of gravitation, F=Gm1m2r122F = \dfrac{Gm_1m_2}{r_{12}^2} .

If the large object is spherically symmetric, we may replace it with a point with the same mass located at the center of the sphere. Therefore, the force will be

F=6.671011Nm2/kg21kg61024kg(6.4106m)2=9.77NF= \dfrac{6.67\cdot10^{-11}\,\mathrm{N m^2/kg^2}\cdot1\,\mathrm{kg}\cdot6\cdot10^{24}\,\mathrm{kg}}{(6.4\cdot10^6\,\mathrm{m})^2} = 9.77\,\mathrm{N}


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