a) Time of flight for a projectile, T=2Usingθ
U=50m/s
θ=?
g=10m/s2
However, maximum height, H=U2sin22gθ
H=100m
Hence, 100=502sin22×10θ
sin2θ=5022×10×100=0.8
sinθ=0.8944
Therefore, T=102×50×0.8944=8.9s
b) sinθ=0.8944
Using Natural Sine Table (Trigonometrical Tables)
θ, angle of projection = 63,4o1'
c) Range, R=gU2sin2θ=10502sin(2×63.4o1′)=250×0.8007=200.2m
Answer: a) T = 8.9 s; b) θ = 63,4o1'; c) R = 200.2 m.
Comments
Leave a comment