Question #163065

The star of a distant solar system explodes as a supernova. At the moment of the explosion, an resting exploration spaceship is 15 AU away from the shock wave. The shock wave of the explosion travels with 25000 km/s towards the spaceship. To save the crew, the spacecraft makes use of a special booster that uniformly accelerates at 150 m/s2 in the opposite direction. Determine if the crew manages to escape from the shock wave. (Neglect relativistic effects.)


Expert's answer

Let us determine the equations of motion of the shock and of the spaceship. Let the supernova be in the origin of the coordinate system. Therefore, the x-coordinate of the shock wave will be

x1(t)=vshockt=2.5107m/st.x_1(t) = v_{\text{shock}}\cdot t= 2.5\cdot10^7\,\mathrm{m/s}\cdot t.

The spaceship is initially at the point with the coordinate x0=15AU=151.5108km=2.251012m.x_0 =15 \,\text{AU} = 15\cdot 1.5\cdot10^{8}\,\mathrm{km} = 2.25\cdot10^{12}\,\mathrm{m}.

The spaceship moves with constant acceleration, so its coordinate after t seconds will be

x2(t)=x0+v0t+at22=2.251012m+0+150t22.x_2(t) = x_0 + v_0t + \dfrac{at^2}{2} = 2.25\cdot10^{12}\,\mathrm{m} + 0 + \dfrac{150\cdot t^2}{2}.

The crew will escape if its coordinate is greater than the coordinate of shock. Let us determine if the shock overtakes the spaceship

2.251012+150t22=2.5107t,4.51012+150t2=5107t,150t25107t+4.51012=0.2.25\cdot10^{12} + \dfrac{150\cdot t^2}{2} = 2.5\cdot10^7\cdot t,\\ 4.5\cdot10^{12} + 150\cdot t^2 = 5\cdot10^7\cdot t,\\ 150\cdot t^2 - 5\cdot10^7\cdot t + 4.5\cdot10^{12} = 0.

D=b24ac=(5107)241504.51012=21014<0,D = b^2 - 4ac = (5\cdot10^7)^2 - 4\cdot150\cdot4.5\cdot10^{12} = -2\cdot10^{14}< 0, so there are no real roots of the equation. That means, the spaceship will always be ahead the shock.


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