Question #153538

At what distance does a star have an apparent magnitude that is 5 magnitudes brighter (smaller) than its absolute magnitude?


1
Expert's answer
2021-01-01T14:54:30-0500

Let's apply the formula

M=m+55lg(r)M=m+5-5 \lg{(r)}

Where

MM- absolute magnitude

mm- apparent magnitude

where do we write

Mm=55lg(r)M-m=5-5 \lg{(r)}

by problem statement

Mm=5M-m=5

then

5=55lg(r)5=5-5 \lg{(r)}

55=5lg(r)5-5=-5 \lg{(r)}

0=5lg(r)0=-5 \lg{(r)}

0=lg(r)0=\lg{(r)}

from where

r=1pcr=1 pc


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