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Question #147389
Estimate the rate of hydrogen fusion at the sun’s core. You may assume the following:
Average energy emission per hydrogen atom in hydrogen fusion = 6.55 MeV
The luminosity of the Sun = 3.86 ×10^26 J/S
Expert's answer
The rate of hydrogen fusion at the sun’s core:
P
E
=
3.86
⋅
1
0
26
6.55
⋅
1.6
⋅
1
0
−
13
=
3.68
⋅
1
0
38
s
−
1
\frac{P}{E}=\frac{3.86 \cdot10^{26}}{6.55\cdot1.6\cdot10^{-13}}=3.68\cdot10^{38}\ s^{-1}
E
P
=
6.55
⋅
1.6
⋅
1
0
−
13
3.86
⋅
1
0
26
=
3.68
⋅
1
0
38
s
−
1
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