Question #147389

Estimate the rate of hydrogen fusion at the sun’s core. You may assume the following:
Average energy emission per hydrogen atom in hydrogen fusion = 6.55 MeV
The luminosity of the Sun = 3.86 ×10^26 J/S

Expert's answer

The rate of hydrogen fusion at the sun’s core:


PE=3.8610266.551.61013=3.681038 s1\frac{P}{E}=\frac{3.86 \cdot10^{26}}{6.55\cdot1.6\cdot10^{-13}}=3.68\cdot10^{38}\ s^{-1}


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