According to the third Kepler's law,
(m+M)P2=a3 ⇒ m+M=a3P2=10352=100025=40\displaystyle (m+M) P^2 = a^3 \; \; \Rightarrow \; \; m+M = \frac{a^3}{P^2} = \frac{10^3}{5^2} =\frac{1000}{25} = 40(m+M)P2=a3⇒m+M=P2a3=52103=251000=40 solar masses.
Answer: 40 solar masses.
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