Question #105280
Calculate the ratio of temp of stars1 wih absolute magnitude_3and radius_72and star 2 with magnitude 8and radius 6
1
Expert's answer
2020-03-13T10:56:57-0400

We have

M1=3mM_1=3^m

R1=72R_1=72

M2=8mM_2=8^m

R2=6R_2=6

Record the luminosities of each star

L1=4πR12σT14L_1=4\pi R_1^{2}\sigma T_1^{4}

L2=4πR22σT24L_2=4\pi R_2^{2}\sigma T_2^{4}

We apply the Pogson formula

L2L1=2.512M1M2\frac{L_2}{L_1}=2.512^{M_1-M_2}

Substitute luminosities

4πR22σT244πR12σT14=2.512M1M2\frac{4\pi R_2^{2}\sigma T_2^{4}}{4\pi R_1^{2}\sigma T_1^{4}}=2.512^{M_1-M_2}

Simplify the expression

R22T24R12T14=2.51238\frac{ R_2^{2} T_2^{4}}{R_1^{2}T_1^{4}}=2.512^{3-8}

R22T24R12T14=2.5125=0.01\frac{ R_2^{2} T_2^{4}}{R_1^{2}T_1^{4}}=2.512^{-5}=0.01

Where will we write

T2T1=0.01R12R224\frac{ T_2}{T_1}=\sqrt[4]{0.01 \cdot \frac{R_1^{2}}{R_2^{2}}}

T2T1=0.01722624=0.011444=1.095\frac{ T_2}{T_1}=\sqrt[4]{0.01 \cdot \frac{72^{2}}{6^{2}}}=\sqrt[4]{0.01 \cdot 144}=1.095


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