Question #6740

an object vibrates 61440 times in a minute. if the velocity of the sound in the air is 330m/s. find the frequency of the sound in hertz and the wave length

Expert's answer

An object vibrates 61440 times in a minute. if the velocity of the sound in the air is 330m/s330\mathrm{m/s}. find the frequency of the sound in hertz and the wave length

Frequency of the sound will be equal to the frequency of object:


f=614401min=6144060s=1024s1=1024Hzf = \frac{61440}{1\mathrm{min}} = \frac{61440}{60\mathrm{s}} = 1024\mathrm{s}^{-1} = 1024\mathrm{Hz}


Wave length can be found from equation:


λ=csf\lambda = \frac{c_s}{f}


Where csc_s - the speed of sound.


λ=330m/s1024Hz0.322m\lambda = \frac{330\mathrm{m/s}}{1024\mathrm{Hz}} \cong 0.322\mathrm{m}


Answer: f=1024Hz,λ0.322mf = 1024\mathrm{Hz}, \lambda \cong 0.322\mathrm{m}

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