Answer to Question #6714 in Acoustics for harjyot singh

Question

hello,
see, none of the books have been explicit about this so I wanted to clarify my theory,
so what I want to ask is,
when a person wears a eyeglass for say myopia, he is correction his lowest accomidation by adding a negative power,? for example,
a person has the farthest point 100 cm,
so his power (in current state) would be =
100*(1/100+10/25) = 41D . now to see objects at say infinity, we must have power 40D(we know that) so, the power of the lenses should be 40D-41D = -1D. ? I mean so that when an object is at infinity, it will create a virtual image at 100cm (the farthest point of the eye) and from there the eye would be able to focus it, with the power 41D only? so what i mean to say is that a corrective lens corrects the accomodation of an eye(which is between 40D - 44D)? plus whenever a object is placed say nearer to than infinity but more than the farthest point, say 500cm,first the corrective lens makes a virtual image (at a distanc < 100 cm) and then our eye will adjust the focal length. and thus the power should be > 41 D(cause that's the lowest that eye can go upto)
and I see that when we subtract -1D (power of lense) frying the power to focused this virtual image, I find its equal to the power an eye without myopia would needy to focus the object at 500 cm. so Am I right?

plus one more query,
how can we look at closer objects clearly while wearing glasses to look at distant things!
please reply
thank you