Question

hello sir please help me to find my ans. in esy steps.
my que. is :

Area of a windows is 2 m^2 & the intensity level at the open windows is 80 dB. then, how much acoustic power enters the room ?

please reply too soon. thnk u.

Answer 1

Answer on Question #48085-Physics-Acoustics

Area of a window is $A = 2\,m^2$ & the intensity level at the open window is $\beta = 80\,dB$. then, how much acoustic power enters the room?

Solution

The intensity level is:

$$\beta = 10 \log_{10} \frac{I}{I_0},$$

where $I_0 = 10^{-12} \frac{W}{m^2}$,

The sound intensity is

$$80 = 10 \log_{10} \frac{I}{10^{-12} \frac{W}{m^2}} \rightarrow I = 10^{-4} \frac{W}{m^2}.$$

The acoustic power is

$$P = IA = 10^{-4} \frac{W}{m^2} \cdot 2\,m^2 = 2 \cdot 10^{-4} W.$$

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