Question #44702

The velocity of a particle is v=5+2 (a1+a2t) where a1and a2 are constants and t is the time. What is the eccelaration oif the particle.

Expert's answer

Answer on Question #44702, Physics, Mechanics | Kinematics | Dynamics

Question:

The velocity of a particle is v=5+2(a1+a2t)v = 5 + 2(a1 + a2t) where a1a1 and a2a2 are constants and tt is the time. What is the acceleration of the particle.

Answer:

Acceleration of the particle equals:


a=dvdta = \frac{dv}{dt}


where vv is velocity of the particle, tt is time.

Therefore:


a=ddt(5+2(a1+a2t))=a2a = \frac{d}{dt} \left(5 + 2(a1 + a2t)\right) = a2


Answer: a2

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