Question

In 100 seconds a smoke alarm emits 1 000 000 sound waves. What is the frequency of the sound waves?

Answer 1

Answer on Question #42751 – Physics – Acoustics

In 100 seconds a smoke alarm emits 1 000 000 sound waves. What is the frequency of the sound waves?

Solution:

$t = 100 \, \text{s}$ – time of the measurement;

$N = 1\,000\,000$ – number of oscillations;

Formula for the frequency (T – period):

$$f = \frac{1}{T} = \frac{1}{\frac{t}{N}} = \frac{1}{\frac{100 \, \text{s}}{1\,000\,000}} = 10\,000 \, \text{Hz}$$

Answer: frequency of oscillation of a smoke alarm is equal to $10\,000 \, \text{Hz}$.

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