Symbolic Logic
2. Construct proofs for the following arguments.
~(3x)(Px' Qx' (Rx = Tx», (x)(Px = (~ Sx v (Ax ::J Bx»), ~(3x)(Ax' ~ Sx), ~ (3x)(Qx' ~ (Px v Tx», (x)«Px = Rx) ::J Ax) I .". (x)(Qx ::J (Tx v Bx»
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