Three resistors of 10, 12 and 15 ohms are connected in parallel. Evaluate the value of current to the parallel system that will make the current in the 10 ohm resistor equal to 2 A.
Potential difference across 10Ω=V=IR=2×10=20 volts10\Omega=V=IR=2\times 10 =20\ volts10Ω=V=IR=2×10=20 volts
As the resistors are in parallel, therefore potential difference across all resistors will be same.
∴\therefore∴ Current in 12Ω=2012A12\Omega=\frac{20}{12} A12Ω=1220A
Current in 15Ω=2015A15\Omega=\frac{20}{15}A15Ω=1520A
So, total current =(2+2012+2015)A=120+100+8060=5A=(2+\frac{20}{12}+\frac{20}{15})A=\frac{120+100+80}{60}=5A=(2+1220+1520)A=60120+100+80=5A
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