Answer to Question #132433 in Other for Nothando

Question

Solution for x and y
Y=x+4 and
Y=2x^2+6x_8

Answer 1

$y = x+4\\ y = 2x^2+6x-8\\ x+4 = 2x^2+6x-8 \\ 2x^2+6x-8 - x - 4 = 0\\ 2x^2+5x-12 = 0\\ x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ x_1 = \frac{-5+\sqrt{5^2-4×2×(-12)}}{2×2}=1.5\\ x_2 = \frac{-5-\sqrt{5^2-4×2×(-12)}}{2×2}=-4\\$

From here, y =:

$y_1 = x_1 + 4 = 1.5 + 4 = 5.5 \\ y_2 = x_2 + 4 = -4 + 4 = 0$

Answer: (1) 1.5 and 5.5, (2) -4 and 0.