Question

Calculate the weight (kg) of parboiled with 40% MC (wb) required yield 1 ton of desired paddy with 12% MC (wb)

Answer 1

$$Solution$$

$W_f=W_i*\frac{100-MC_i}{100-MC_f}$

$MC_{i}=40$ %

$MC_{f}=12$ %

$MC_{wb}=$ $Moisture$ $Content$ $Wet$ $Basis$ [%]

$W_i=$ $Initial$ $Weight$

$W_f=$ $Final$ $Weight=$ $1 ton$ $=1000kg$

$1000kg=W_i(\frac{100-40}{100-12})=W_i(\frac{60}{88})$

$W_i=\frac{1000}{\frac{60}{88}}=1466.70577kg$ $of$ $paddy$ $at$ $40$% $MC_{wb}$