Answer to Question #115423 in Other for Jafar Abbas

Question #115423

the plates of a parallel plate capacitor,5.0x10^-3m apart are maintained at a potential difference of 5.0x10^4 calculate the magnitude of the i. electric field intensity between the plates ii. force on the electron.

Expert's answer

For a parallel plate capacitor, "E=V\/d"

"\\implies E=5*10^4\/5*10^{-3}=10^7Vm^{-1}"

"Force =qE=1.6*10^{-19}*10^7=1.6*10^{-12} N"

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