Question #102208
If the units of force, energy and velocity in a new system are 10N, 5J and 0.5m/s respectively ,find the units of mass ,length and time in that system
1
Expert's answer
2020-02-03T08:33:36-0500

[Energy]=[Force]×[length][Energy] = [Force]\times [length]

Units of energy:

1J=1N×m1J= 1N\times m


[velocity]=[lenght][time][velocity] = \frac{[lenght]}{[time]}

Units of velocity:

m/s=msm/s=\frac{m}{s}


[Force]=[mass]×[acceleration]=[mass]×[velocity][time]=[mass]×[length][time]2[Force ] = [mass] \times[acceleration] = \frac{[mass]\times[velocity]}{[time]}= \frac{[mass]\times[length]}{[time]^2}

Units of Force:

1N=1kg×ms21N = \frac{1kg\times m}{s^2}


Obviously we can express length through force and energy

[length]=[Energy][Force][length] = \frac{[Energy]}{[Force]}

Unit of length = unit of energy divide by unit of force

5J10N=5N×m10N=0.5m\frac{5J}{10N}= \frac{5N\times m}{10N}=0.5m


[time]=[length][velocity][time] = \frac{[length]}{[velocity]}

Unit of time= unit of velocity divide by unit of length

0.5m0.5ms=1s\frac{0.5 m}{0.5\frac{m}{s}} = 1s


[mass]=[Force]×[time]2[length][mass] =\frac{[Force]\times[time]^2}{[length]}

10N×s20.5m=20kg×m×s2m×s2=20kg\frac{10N\times s^2}{0.5m}=\frac{20{kg\times m}\times s^2}{m\times s^2}= 20 kg


Units of length 0.5 meters

Units of time 1 second

Units of mass 20 kilograms


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