Show that in a finite dimensional vector space V(F) whose basic set is B={x₁,x₂,...xₙ} every vector x∈V is uniquely expressible as linear combination of the vector in B.
In the vector space Vs(Rₙ) let α=(1,2,1), β=(3,1,5), -γ=(3,-4,7) prove that the sub space planned by S={α,β} and T={α,β,γ} are same.
In the vector space Vs(Rₙ) let α=(1,2,1), β=(3,1,5), -γ=(3,-4,7) prove that the sub space planned by S={α,β} and T={α,β,γ} are same.
If p(x) denotes the set of all polynomials one indeterminates x over field F, then show that p(x) is a vector space over F with addition defined as addition of polynomials and scalar multiplication defined as the product of polynomials by an element of F. i.e if p(x)={p(x)/p(x)=a₀+a₁x+...+aₙxₙ...}={∑∞,ₙ₌∞ aₙxⁿ for as ∈ f}.
Define addition and scalar multiplication to prove.
If p(x) denotes the set of all polynomials one indeterminates x over field F, then show that p(x) is a vector space over F with addition defined as addition of polynomials and scalar multiplication defined as the product of polynomials by an element of F. i.e if p(x)={p(x)/p(x)=a₀+a₁x+...+aₙxₙ...}={∑∞,ₙ₌∞ aₙxⁿ for as ∈ f}.
Define addition and scalar multiplication to prove.
Let V be set of real valued continuous function defined as [0,1] such that f(0/3)=2. Show that V is not a vector space over R (reals) under addition and scalar multiplication defined as : (f+g)(x)=f(x)+g(x) for all f,g € V.
(alpha f)(x)= alpha f(x) for all alpha € R, f€V.
Let V be set of real valued continuous function defined as [0,1] such that f(0/3)=2. Show that V is not a vector space over R (reals) under addition and scalar multiplication defined as : (f+g)(x)=f(x)+g(x) for all f,g € V.
(alpha f)(x)= alpha f(x) for all alpha € R, f€V.
((p⟶q)v(q⟶p))⇔p⟷q
b) Construct a truth table to determine whether the following compound statement is a tautology, a contradiction or a contingency.
~(p∧r)⟶~(q∨r)
c) Use the laws of logic to establish the following logical expression.
~(p∨q) v (~p∧q)⟺~p
Solve the following spherical triangle using Law of Sine and Cosine
A= 137°28´, C=135°44´, c= 160° Find : a
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