Question #9068

if a+b+c=0, |a|=3, |b|=5 and |c|=7, then find the angle between a and b.

Expert's answer

if a+b+c=0a + b + c = 0, a=3|a| = 3, b=5|b| = 5 and c=7|c| = 7, then find the angle between aa and bb.


c2=a2+b22abcosγc^2 = a^2 + b^2 - 2ab * cos\gamma72=32+52235cosγ7^2 = 3^2 + 5^2 - 2 * 3 * 5 * cos\gamma49=9+2530cosγ49 = 9 + 25 - 30 * cos\gamma4934=30cosγ49 - 34 = -30 * cos\gamma15=30cosγ15 = -30 * cos\gamma12=cosγ-\frac{1}{2} = cos\gammaγ=arccos(12)\gamma = \arccos\left(-\frac{1}{2}\right)γ=2π3=120\gamma = \frac{2\pi}{3} = 120{}^\circ


Answer:


γ=120\gamma = 120{}^\circ

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