Answer on Question #56125 – Math – Vector Calculus
Let φ=2x∧z∧4−x∧2y, find
∣∇φ∣
5(v97)
3(v112)
(v105)
2(v93)
Solution
∇φ=(∂x∂φ,∂y∂φ,∂z∂φ)=(∂x∂(2xz4−x2y),∂y∂(2xz4−x2y),∂z∂(2xz4−x2y))=(2z4−2xy,−x2,8xz3).∣∇φ∣=(2z4−2xy)2+(−x2)2+(8xz3)2.
If we need the number in the answer we need to choose a point (x0,y0,z0) where we calculate ∣∇φ∣.
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