Question #56125

Let
ϕ=2x^z^4−x^2y
,find
|▽ϕ|

5(√97)

3(√112)

(√105)

2(√93)
1

Expert's answer

2015-11-09T00:00:47-0500

Answer on Question #56125 – Math – Vector Calculus

Let φ=2xz4x2y\varphi = 2x^{\wedge}z^{\wedge}4 - x^{\wedge}2y, find


φ|\nabla \varphi|


5(v97)

3(v112)

(v105)

2(v93)

Solution

φ=(φx,φy,φz)=((2xz4x2y)x,(2xz4x2y)y,(2xz4x2y)z)=(2z42xy,x2,8xz3).\nabla \varphi = \left(\frac{\partial \varphi}{\partial x}, \frac{\partial \varphi}{\partial y}, \frac{\partial \varphi}{\partial z}\right) = \left(\frac{\partial (2xz^4 - x^2y)}{\partial x}, \frac{\partial (2xz^4 - x^2y)}{\partial y}, \frac{\partial (2xz^4 - x^2y)}{\partial z}\right) = (2z^4 - 2xy, -x^2, 8xz^3).φ=(2z42xy)2+(x2)2+(8xz3)2.|\nabla \varphi| = \sqrt{(2z^4 - 2xy)^2 + (-x^2)^2 + (8xz^3)^2}.


If we need the number in the answer we need to choose a point (x0,y0,z0)(x_0, y_0, z_0) where we calculate φ|\nabla \varphi|.

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