Question #56119

4 Evaluate
(A+B).(A−B)
if
A=2i−3j+5k
and
B=3i+j−2k
20
22
24
26
1

Expert's answer

2015-11-06T00:00:47-0500

Answer on Questionn #56119 – Math – Vector Calculus

Evaluate (A+B)(AB)(A + B) * (A - B) if A=2i3j+5kA = 2i - 3j + 5k and B=3i+j2kB = 3i + j - 2k.

a) 20

b) 22

c) 24

d) 26

Solution

First find A+BA + B and ABA - B

A+B=(2i3j+5k)+(3i+j2k)=5i2j+3kA + B = (2i - 3j + 5k) + (3i + j - 2k) = 5i - 2j + 3kAB=(2i3j+5k)(3i+j2k)=i4j+7kA - B = (2i - 3j + 5k) - (3i + j - 2k) = -i - 4j + 7k


Now, we can find the scalar product (dot product) of these vectors. Remember that for the unit vectors following identity holds ii=jj=kk=1i * i = j * j = k * k = 1 and ij=ik=jk=0i * j = i * k = j * k = 0

(A+B)(AB)=(5i2j+3k)(i4j+7k)=5ii20ij+35ik+2ij+8jj14jk3ik12jk+21kk=5+8+21=24\begin{array}{l} (A + B) * (A - B) = (5i - 2j + 3k) * (-i - 4j + 7k) \\ = -5ii - 20ij + 35ik + 2ij + 8jj - 14jk - 3ik - 12jk + 21kk \\ = -5 + 8 + 21 = 24 \\ \end{array}


Answer: c) 24.

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