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Answer on Question #56117 – Math – Vector Calculus
Let A=i+3j-2k and B=4i-2j+4k, find (2A+B)(^A-2B)
-14
-21
-10
-5
Solution
2A=2i+6j-4k;
2B=8i-4j+8k;
(2A+B)(A−2B)=(2i+6j−4k+4i−2j+4k)(i+3j−2k−8i−4j+8k)=(6i+4j)(−7i+7j−10k)=6(−7)+47+010=−42+28=−14.
Answer: -14.
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