Question #56115

Simplify
(A+B).(B+C)×(C+A)

a). B×C

b). 2.A×B

c). 2.A×C

d). A×B×C
1

Expert's answer

2015-11-10T00:00:48-0500

Answer on Question #56115 – Math - Vector Calculus

Question

Simplify


(A+B).(B+C)×(C+A)(A + B). (B + C) \times (C + A)


a). B×CB \times C

b). 2.A×B2. A \times B

c). 2.A×C2. A \times C

d). A×B×CA \times B \times C

Solution

By the properties of cross product, calculate


(A+B)((B+C)×(C+A))=(A+B)(B×C+B×A+C×C+C×A)=(A+B)(B×C+B×A+0+C×A)=AB×C+AB×A+AC×A+BB×C+BB×A+BC×A=AB×C+0+0+0+0+BC×A=2AB×C.\begin{array}{l} (\vec{A} + \vec{B}) \cdot \left((\vec{B} + \vec{C}) \times (\vec{C} + \vec{A})\right) = (\vec{A} + \vec{B}) \cdot (\vec{B} \times \vec{C} + \vec{B} \times \vec{A} + \vec{C} \times \vec{C} + \vec{C} \times \vec{A}) \\ = (\vec{A} + \vec{B}) \cdot (\vec{B} \times \vec{C} + \vec{B} \times \vec{A} + 0 + \vec{C} \times \vec{A}) \\ = \vec{A} \cdot \vec{B} \times \vec{C} + \vec{A} \cdot \vec{B} \times \vec{A} + \vec{A} \cdot \vec{C} \times \vec{A} + \vec{B} \cdot \vec{B} \times \vec{C} + \vec{B} \cdot \vec{B} \times \vec{A} + \vec{B} \cdot \vec{C} \times \vec{A} \\ = \vec{A} \cdot \vec{B} \times \vec{C} + 0 + 0 + 0 + 0 + \vec{B} \cdot \vec{C} \times \vec{A} = 2 \cdot \vec{A} \cdot \vec{B} \times \vec{C}. \end{array}


Answer. 2AB×C2 \cdot \vec{A} \cdot \vec{B} \times \vec{C}

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