Question #56112

Evaluate
|(A+B).(A−B)|
if
A=2i−3j+5k
and
B=3i+j−2k

√24

√240

√530

√525
1

Expert's answer

2015-11-07T00:00:48-0500

Answer on Question #56112– Math – Vector Calculus

Given that A=2i3j+5kA = 2i - 3j + 5k, B=3i+j2kB = 3i + j - 2k

Find (A+B)(AB)|(A + B) \cdot (A - B)|

Solution


A+B=2i3j+5k+3i+j2k=5i2j+3kA + B = 2i - 3j + 5k + 3i + j - 2k = 5i - 2j + 3kAB=2i3j+5k3ij+2k=i4j+7kA - B = 2i - 3j + 5k - 3i - j + 2k = -i - 4j + 7k


The Dot product formula:


ab=axbx+ayby+azbza \cdot b = a_x b_x + a_y b_y + a_z b_z


Then


(A+B)(AB)=5(1)2(4)+37=24(A + B) \cdot (A - B) = 5 \cdot (-1) - 2 \cdot (-4) + 3 \cdot 7 = 24(A+B)(AB)=(A+B)(AB)=24|(A + B) \cdot (A - B)| = (A + B) \cdot (A - B) = 24


Answer:


(A+B)(AB)=24|(A + B) \cdot (A - B)| = 24


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