Answer on Question #52180 – Math – Vector Calculus
Question
Let a = 2 i − j a = 2i - j a = 2 i − j and b = i + j + k b = i + j + k b = i + j + k , evaluate a × b a \times b a × b .
3 k + 2 j − i i + 2 j + 3 k 3k + 2j - i \\
i + 2j + 3k 3 k + 2 j − i i + 2 j + 3 k 3 k − 2 j − i i + 2 j − 3 k 3k - 2j - i \\
i + 2j - 3k 3 k − 2 j − i i + 2 j − 3 k Solution
If a = 2 i − j a = 2i - j a = 2 i − j and b = i + j + k b = i + j + k b = i + j + k , then the cross product a × b a \times b a × b is
a × b = ∣ i j k 2 − 1 0 1 1 1 ∣ = i ∣ − 1 0 1 1 ∣ − j ∣ 2 0 1 1 ∣ + k ∣ 2 − 1 1 1 ∣ = i ( − 1 ∗ 1 − 1 ∗ 0 ) − j ( 2 ∗ 1 − 1 ∗ 0 ) + k ( 2 ∗ 1 − 1 ) ( − 1 ) ) = − i − 2 j + 3 k . \begin{array}{l}
a \times b = \left| \begin{array}{ccc}
i & j & k \\
2 & -1 & 0 \\
1 & 1 & 1
\end{array} \right| = i \left| \begin{array}{cc}
-1 & 0 \\
1 & 1
\end{array} \right| - j \left| \begin{array}{cc}
2 & 0 \\
1 & 1
\end{array} \right| + k \left| \begin{array}{cc}
2 & -1 \\
1 & 1
\end{array} \right| \\
= i(-1 * 1 - 1 * 0) - j(2 * 1 - 1 * 0) + k(2 * 1 - 1)(-1)) = -i - 2j + 3k.
\end{array} a × b = ∣ ∣ i 2 1 j − 1 1 k 0 1 ∣ ∣ = i ∣ ∣ − 1 1 0 1 ∣ ∣ − j ∣ ∣ 2 1 0 1 ∣ ∣ + k ∣ ∣ 2 1 − 1 1 ∣ ∣ = i ( − 1 ∗ 1 − 1 ∗ 0 ) − j ( 2 ∗ 1 − 1 ∗ 0 ) + k ( 2 ∗ 1 − 1 ) ( − 1 )) = − i − 2 j + 3 k .
Answer: a × b = 3 k − 2 j − i a \times b = 3k - 2j - i a × b = 3 k − 2 j − i .
www.AssignmentExpert.com