Answer on Question #46878 – Math – Vector Calculus
Find the vector product axb. If a = 2 i + 3 j + 4 k a = 2i + 3j + 4k a = 2 i + 3 j + 4 k and b = 5 i − 2 j + k b = 5i - 2j + k b = 5 i − 2 j + k
Solution
11 i + 18 j − 19 k 2 j + 3 k 5 i − 6 j + 7 k 4 i − 6 j + 11 k \begin{array}{l}
11i + 18j - 19k \\
2j + 3k \\
5i - 6j + 7k \\
4i - 6j + 11k \\
\end{array} 11 i + 18 j − 19 k 2 j + 3 k 5 i − 6 j + 7 k 4 i − 6 j + 11 k
By the definition of vector product
[ a , b ] = ∣ i j k 2 3 4 5 − 2 1 ∣ = 3 ⋅ 1 ⋅ i + 4 ⋅ 5 ⋅ j + 2 ⋅ ( − 2 ) ⋅ k − 3 ⋅ 5 ⋅ k − 4 ⋅ ( − 2 ) ⋅ i − 1 ⋅ 2 ⋅ j = = 11 i + 18 j − 19 k \begin{array}{l}
[a, b] =
\begin{vmatrix}
\boldsymbol{i} & \boldsymbol{j} & \boldsymbol{k} \\
2 & 3 & 4 \\
5 & -2 & 1
\end{vmatrix}
= 3 \cdot 1 \cdot \boldsymbol{i} + 4 \cdot 5 \cdot \boldsymbol{j} + 2 \cdot (-2) \cdot \boldsymbol{k} - 3 \cdot 5 \cdot \boldsymbol{k} - 4 \cdot (-2) \cdot \boldsymbol{i} - 1 \cdot 2 \cdot \boldsymbol{j} = \\
= 11i + 18j - 19k \\
\end{array} [ a , b ] = ∣ ∣ i 2 5 j 3 − 2 k 4 1 ∣ ∣ = 3 ⋅ 1 ⋅ i + 4 ⋅ 5 ⋅ j + 2 ⋅ ( − 2 ) ⋅ k − 3 ⋅ 5 ⋅ k − 4 ⋅ ( − 2 ) ⋅ i − 1 ⋅ 2 ⋅ j = = 11 i + 18 j − 19 k
Answer: a
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