Answer on Question #44083, Math, Vector Calculus
Prove that ∣(a−1+(b))−1×(a−1−(b))−1∣=2ab|(a^{-1} + (b))^{-1} \times (a^{-1} - (b))^{-1}| = 2ab∣(a−1+(b))−1×(a−1−(b))−1∣=2ab. If a−1⊥b−1a^{-1} \perp b^{-1}a−1⊥b−1.
**Solution.**
If a⃗⊥b⃗\vec{a} \perp \vec{b}a⊥b, then ∣a⃗×b⃗∣=∣a⃗∣∣b⃗∣sin90∘=∣a⃗∣∣b⃗∣|\vec{a} \times \vec{b}| = |\vec{a}||\vec{b}| \sin 90{}^\circ = |\vec{a}||\vec{b}|∣a×b∣=∣a∣∣b∣sin90∘=∣a∣∣b∣.
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