Question #44082

Prove that (a ⃗+3b ⃗)×(a ⃗+b ⃗ )+(3a ⃗-5b ⃗)×(a ⃗-b ⃗) = 0.

Expert's answer

Answer on Question #44082 – Math – Vector Calculus

Prove that (a+3b)×(a+b)+(3a5b)×(ab)=0(a + 3b) \times (a + b) + (3a - 5b) \times (a - b) = 0

Solution.


(a+3b)×(a+b)=(a×a)+3(b×a)+3(b×b)+(a×b);(a + 3b) \times (a + b) = (a \times a) + 3(b \times a) + 3(b \times b) + (a \times b);(3a5b)×(ab)=3(a×a)3(a×b)5(b×a)+5(b×b).(3a - 5b) \times (a - b) = 3(a \times a) - 3(a \times b) - 5(b \times a) + 5(b \times b).


Since, (a×a)=0(a \times a) = 0 and (b×b)=0(b \times b) = 0, we obtain


(a+3b)×(a+b)+(3a5b)×(ab)=3(b×a)+(a×b)3(a×b)5(b×a).(a + 3b) \times (a + b) + (3a - 5b) \times (a - b) = 3(b \times a) + (a \times b) - 3(a \times b) - 5(b \times a).


As


(a×b)=(b×a),(a \times b) = -(b \times a),


we have


(a+3b)×(a+b)+(3a5b)×(ab)=3(a×b)+(a×b)3(a×b)+5(a×b)=0.(a + 3b) \times (a + b) + (3a - 5b) \times (a - b) = -3(a \times b) + (a \times b) - 3(a \times b) + 5(a \times b) = 0.


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